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Java Satunnainen nextInt() -menetelmä

Random-luokan nextInt()-metodi palauttaa seuraavan näennäissatunnaisen, tasaisesti jakautuneen int-arvon satunnaislukugeneraattorin sekvenssistä.

Syntaksi

 public int nextInt() 

Parametrit

ETTÄ

Palautusarvo

nextInt()-metodi palauttaa seuraavan näennäissatunnaisen int-arvon, joka on vedetty satunnaislukugeneraattorin sekvenssistä.

Esimerkki 1

 import java.util.Random; public class JavaRandomNextIntExample1 { public static void main(String[] args) { Random random = new Random(); //return the next pseudorandom integer value Integer val = random.nextInt(); System.out.println('Random Integer value : '+val); Integer val1 = random.nextInt(); System.out.println('Random Integer value : '+val1); } } 
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Lähtö:

 Random Integer value : -298063488 Random Integer value : 1400961289 

Java Satunnainen nextInt() -menetelmä

Satunnaisluokan nextInt(int n) -metodi palauttaa näennäissatunnaisen int-arvon nollan (sisältää ) ja määritellyn arvon (poissulkeva) väliltä, ​​joka on vedetty satunnaislukugeneraattorin sekvenssistä.

Syntaksi

 public int nextInt(int n) 

Parametrit

n : Se on palautettavan satunnaisluvun raja. Sen on oltava positiivista.

Palautusarvo

nextInt()-metodi palauttaa seuraavan näennäissatunnaisen int-arvon nollan ja n:n välillä, joka on otettu satunnaislukugeneraattorin sekvenssistä.

Heitä

nextInt()-metodi heittää IllegalArgumentExceptionin, jos n ei ole positiivinen.

Esimerkki 2

 import java.util.Random; public class JavaRandomNextIntExample2 { static int j=1; public static void main(String[] args) { Random random = new Random(); for (int i=1;i<8;i++) { return the next pseudorandom integer value val="random.nextInt(i);" system.out.println(j++ +'. random intvalue : '+val+' '); } < pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> 1. Random intvalue : 0 2. Random intvalue : 1 3. Random intvalue : 0 4. Random intvalue : 3 5. Random intvalue : 1 6. Random intvalue : 0 7. Random intvalue : 0 </pre> <h2>Example 3</h2> <pre> import java.util.Random; import java.util.Scanner; import java.util.concurrent.ArrayBlockingQueue; public class JavaRandomNextIntExample3 { static int j=1; public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print(&apos;Enter number of players.&apos;); int capacity = scanner.nextInt(); ArrayBlockingQueue queue = new ArrayBlockingQueue(capacity); System.out.println(&apos;Enter name of &apos; + capacity + &apos; Players.&apos;); for (int i = 0; i <capacity; i++) { system.out.print(j++ + ' '); string str="scanner.next();" queue.add(str); } j="1;" random random(); for (string xyz : queue) integer val="random.nextInt(capacity);" system.out.println(j++ +'. +xyz+' will have '+val+' bonus points.'); < pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Enter number of players.3 Enter name of 3 Players. 1 Sukla 2 Mukta 3 Amar 1. Sukla will have 0 bonus points. 2. Mukta will have 1 bonus points. 3. Amar will have 2 bonus points. </pre> <h2>Example 4</h2> <pre> import java.util.Random; public class JavaRandomNextIntExample4 { public static void main(String[] args) { Random random = new Random(); //return the next pseudorandom integer value Integer val = random.nextInt(0); System.out.println(&apos;Random Integer value : &apos;+val); } } </pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Exception in thread &apos;main&apos; java.lang.IllegalArgumentException: bound must be positive atjava.util.Random.nextInt(Random.java:388) at com.javaTpoint.JavaRandomNextIntExample4.main(JavaRandomNextIntExample4.java:9) </pre> <h4>Note: The bound value must be positive else it will give IllegalArgumentException.</h4></capacity;></pre></8;i++)>

Esimerkki 3

 import java.util.Random; import java.util.Scanner; import java.util.concurrent.ArrayBlockingQueue; public class JavaRandomNextIntExample3 { static int j=1; public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print(&apos;Enter number of players.&apos;); int capacity = scanner.nextInt(); ArrayBlockingQueue queue = new ArrayBlockingQueue(capacity); System.out.println(&apos;Enter name of &apos; + capacity + &apos; Players.&apos;); for (int i = 0; i <capacity; i++) { system.out.print(j++ + \' \'); string str="scanner.next();" queue.add(str); } j="1;" random random(); for (string xyz : queue) integer val="random.nextInt(capacity);" system.out.println(j++ +\'. +xyz+\' will have \'+val+\' bonus points.\'); < pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Enter number of players.3 Enter name of 3 Players. 1 Sukla 2 Mukta 3 Amar 1. Sukla will have 0 bonus points. 2. Mukta will have 1 bonus points. 3. Amar will have 2 bonus points. </pre> <h2>Example 4</h2> <pre> import java.util.Random; public class JavaRandomNextIntExample4 { public static void main(String[] args) { Random random = new Random(); //return the next pseudorandom integer value Integer val = random.nextInt(0); System.out.println(&apos;Random Integer value : &apos;+val); } } </pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Exception in thread &apos;main&apos; java.lang.IllegalArgumentException: bound must be positive atjava.util.Random.nextInt(Random.java:388) at com.javaTpoint.JavaRandomNextIntExample4.main(JavaRandomNextIntExample4.java:9) </pre> <h4>Note: The bound value must be positive else it will give IllegalArgumentException.</h4></capacity;>

Esimerkki 4

 import java.util.Random; public class JavaRandomNextIntExample4 { public static void main(String[] args) { Random random = new Random(); //return the next pseudorandom integer value Integer val = random.nextInt(0); System.out.println(&apos;Random Integer value : &apos;+val); } } 
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Lähtö:

 Exception in thread &apos;main&apos; java.lang.IllegalArgumentException: bound must be positive atjava.util.Random.nextInt(Random.java:388) at com.javaTpoint.JavaRandomNextIntExample4.main(JavaRandomNextIntExample4.java:9) 

Huomautus: Rajatun arvon on oltava positiivinen, muuten se antaa IllegalArgumentExceptionin.